実行日時: 2026-09-10T23:17:58(ID: 20260910-231758-8d8689) ← 履歴一覧に戻る
問題TeXソース
¥item $0 ¥leqq ¥theta ¥LEQQ ¥pi$とするとき、次の方程式を解け。
¥begin{edaenumerate}
¥item $¥sin ¥theta = ¥dfrac{¥sqrt{3}}{2}$ ¥vspace{13ZW}
¥item $¥cos ¥theta = ¥dfrac{¥sqrt{2}}{2}$ ¥vspace{13ZW}
¥item $¥tan ¥theta = - ¥dfrac{1}{¥sqrt{3}}$ ¥vspace{13ZW}
¥item $¥sin 2¥theta = ¥dfrac{1}{2}$ ¥vspace{13ZW}
¥end{edaenumerate}
¥item 次の方程式の解を一般角で答えよ。
¥begin{edaenumerate}
¥item $¥sin ¥theta = ¥dfrac{1}{2}$ ¥vspace{13ZW}
¥item $¥cos ¥theta ¥dfrac{¥sqrt{3}}{2}$ ¥vspace{13ZW}
¥item $¥tan ¥theta = - 1$ ¥vspace{13ZW}
¥item $¥cos 3¥theta = ¥dfrac{1}{2}$ ¥vspace{13ZW}
¥end{edaenumerate}
GPT生成 解答TeX(検査前)
\item
\begin{edaenumerate}
\item $\theta=\dfrac{\pi}{3},\ \dfrac{2\pi}{3}$
\item $\theta=\dfrac{\pi}{4}$
\item $\theta=\dfrac{5\pi}{6}$
\item $\theta=\dfrac{\pi}{12},\ \dfrac{5\pi}{12}$
\end{edaenumerate}
\item
\begin{edaenumerate}
\item $\theta=\dfrac{\pi}{6}+2n\pi,\ \dfrac{5\pi}{6}+2n\pi\quad(n\text{は整数})$
\item $\theta=2n\pi\pm\dfrac{\pi}{6}\quad(n\text{は整数})$
\item $\theta=-\dfrac{\pi}{4}+n\pi\quad(n\text{は整数})$
\item $\theta=\dfrac{2n\pi}{3}\pm\dfrac{\pi}{9}\quad(n\text{は整数})$
\end{edaenumerate}
Claudeによる指摘事項
誤りなし
修正後の解答TeX(最終)
\item
\begin{edaenumerate}
\item $\theta=\dfrac{\pi}{3},\ \dfrac{2\pi}{3}$
\item $\theta=\dfrac{\pi}{4}$
\item $\theta=\dfrac{5\pi}{6}$
\item $\theta=\dfrac{\pi}{12},\ \dfrac{5\pi}{12}$
\end{edaenumerate}
\item
\begin{edaenumerate}
\item $\theta=\dfrac{\pi}{6}+2n\pi,\ \dfrac{5\pi}{6}+2n\pi\quad(n\text{は整数})$
\item $\theta=2n\pi\pm\dfrac{\pi}{6}\quad(n\text{は整数})$
\item $\theta=-\dfrac{\pi}{4}+n\pi\quad(n\text{は整数})$
\item $\theta=\dfrac{2n\pi}{3}\pm\dfrac{\pi}{9}\quad(n\text{は整数})$
\end{edaenumerate}